Math in the Workplace - Algebra/Geometry
MICRON TECHNOLOGY, INC.,
Semiconductor Manufacturing
Technical Writer
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Job Description: Responsible for writing content, editing, and formatting the corporate newsletters as well as working with various departments and outside agency to produce the Annual Report. |
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Problem:
The latest issue of the company newsletter needs to include an architect’s
rendering of the new facility. The drawing (which will be scanned by the printer
because it is too large for the in-house scanners) is 31/2 feet wide by 16 inches
high. In preparing the newsletter for the printer, however, the writer must
create a placeholder in the newsletter for the drawing.
The writer wants the graphic to lay across 2 of the 3 columns of text. The
newsletter is a standard 81/2 by 11 inches format, with 1/2-inch margins all
around and 1/4-inch “gutters” between columns. What should the measurements
be for the placeholder? What is the percent of reduction?
 MICRON TECHNOLOGY, INC.
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Solution:
Paper width - margins - gutters 
3 columns = Column Width
8 1/2 - (2 x 1/2) - (2 x 1/4) = 7
3 = 2 1/3 inches wide
2 columns + gutter = Image Width
2 x 2 1/3 = 4 2/3 + 1/4 = 4 11/12 or 4.916 inches Wide
Reduced size Original Size = Percent Reduction
4.916 inches (3.5 ft x 12 in) = 11.7% reduction
Original Height x Percent Reduction = Image Height
16 inches x 11.7% = 1.87 inches High